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y^2-26y-6=0
a = 1; b = -26; c = -6;
Δ = b2-4ac
Δ = -262-4·1·(-6)
Δ = 700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{700}=\sqrt{100*7}=\sqrt{100}*\sqrt{7}=10\sqrt{7}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-10\sqrt{7}}{2*1}=\frac{26-10\sqrt{7}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+10\sqrt{7}}{2*1}=\frac{26+10\sqrt{7}}{2} $
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